• A horizontal conveyer belt moving at a uniform speed of 1.2 M/S transports material at the rate of 100  tonnes/hr. Belt is 200 M long and driven by a motor at 1200 rpm. (a) Determine the load inertia referred to the motor shaft. (b) Calculate the torque that motor should develop to accelerate the belt from standstill to full speed in 8 sec. Moment of inertia of the motor is 0.1 kg-.m²

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Given that For a horizontal belt uniform speed V 12 ms Rate of transport material 100 tonnesh... View the full answer