Let r(t) =(t+1)i+ Then lim r(t)= t1 j+ 9 (1=3) j+ sin(3t) k t + i+...
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Let r(t) =(√t+1)i+ Then lim r(t)= t→1 j+ 9 (1²=3) j+ sin(3πt) k t + i+ k. Let r(t) =(√t+1)i+ Then lim r(t)= t→1 j+ 9 (1²=3) j+ sin(3πt) k t + i+ k.
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