An L9 orthogonal array material processing experiment was designed as follows: Level 2 Level 3 A3...
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An L9 orthogonal array material processing experiment was designed as follows: Level 2 Level 3 A3 = HCL B3= 220 'B C3 = soak D3= H₂O A: Pre treatment B: Treating Temp. C: Treating Method D: Additive The results were: Replication #1 Replication # 2 Exp#. A B 123456789 1 Level 1 A1= HCL B1= 200 'B C1= dip D1= alcohol -222333 1231NUN3 1 1 9 Assume Smaller is better. 3 C 3111W NW N1 2 3 2 2 D 123312231 1 A2 = H₂SO4 B2= 190 'B C2= spray D2= Ethanol 8, 12, 11, 13, 14, 9, 11, 9, 10 7, 9, 12, 13, 19, 12, 8, 13, 11 Results 8 12 11 13 14 9 11 9 10 7 9 12 13 19 12 8 13 11 1. Perform Graphical Analysis of both Average and Variance (using S/N Variance transformation). Please note that for experiment 4, you need to make one of the results = 13.01 for S/N calculations. 2. Perform ANOVA for Average and S/N, determine the best factor settings for Average and S/N based on significance analysis > 5% contribution Taguchi Rule. 3. Determine Expected Value (EV) and Confidence Interval (CI) for Average only based on Average and Variance ANOVA. 4. Perform ANOVA for Average only, determine which factor(s) are significant and % contribution. Use F factor in order to have no significant factors left. 5. Predict the expected value (EV) and confidence interval (CI) for average only, based on average and Variance ANOVA analysis. Since no factors are significant, the EV = the average of the experiment. An L9 orthogonal array material processing experiment was designed as follows: Level 2 Level 3 A3 = HCL B3= 220 'B C3 = soak D3= H₂O A: Pre treatment B: Treating Temp. C: Treating Method D: Additive The results were: Replication #1 Replication # 2 Exp#. A B 123456789 1 Level 1 A1= HCL B1= 200 'B C1= dip D1= alcohol -222333 1231NUN3 1 1 9 Assume Smaller is better. 3 C 3111W NW N1 2 3 2 2 D 123312231 1 A2 = H₂SO4 B2= 190 'B C2= spray D2= Ethanol 8, 12, 11, 13, 14, 9, 11, 9, 10 7, 9, 12, 13, 19, 12, 8, 13, 11 Results 8 12 11 13 14 9 11 9 10 7 9 12 13 19 12 8 13 11 1. Perform Graphical Analysis of both Average and Variance (using S/N Variance transformation). Please note that for experiment 4, you need to make one of the results = 13.01 for S/N calculations. 2. Perform ANOVA for Average and S/N, determine the best factor settings for Average and S/N based on significance analysis > 5% contribution Taguchi Rule. 3. Determine Expected Value (EV) and Confidence Interval (CI) for Average only based on Average and Variance ANOVA. 4. Perform ANOVA for Average only, determine which factor(s) are significant and % contribution. Use F factor in order to have no significant factors left. 5. Predict the expected value (EV) and confidence interval (CI) for average only, based on average and Variance ANOVA analysis. Since no factors are significant, the EV = the average of the experiment.
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1 The graphical analysis of both average and variance showed that the best factor settings ... View the full answer
Related Book For
Probability & Statistics for Engineers & Scientists
ISBN: 978-0130415295
7th Edition
Authors: Ronald E. Walpole, Raymond H. Myers, Sharon L. Myers, Keying
Posted Date:
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