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# 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal

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## 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N 2. This simply supported beam has a circular cross section, and is subjected to the effects of an axial tension force (N-50 KN), a twisting moment (-0.5 kN.m) and a concentrated load at mid-span (P-50 KN) Calculate the principal stresses and their orientation at Points on the cross section at Section n-n. Needed information for a circular section: Area ² For a semi-circular section: N 50 kN T-0.5 kN.m N 1 Point s 24 Point s 0.6 m in y n Section n-n 0.6 m 100 mm 1= 50 KN FI J.= 12m tis 2 (4)/(3 m) N50 KN T-0.5 kNm T N

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## C Slope deflection Point A C B EL O W 012 we View the full answer

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## Advanced Accounting

ISBN: 978-1934319307

2nd edition

Authors: Susan S. Hamlen, Ronald J. Huefner, James A. Largay III

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