By selecting a common base of 100 MVA (PowerWorld's default) and 132 kV at the transmission...

 

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By selecting a common base of 100 MVA (PowerWorld's default) and 132 kV at the transmission line loop, draw an impedance diagram showing all impedances in per-unit. Figure 2 contains all necessary data. Generator G₁: Generator G₂: three-phase A-Y transformer T₁: three-phase Y-A transformer T₂: Load: 50 MVA, 13.2 kV, x = 0.15 pu 20 MVA, 13.8 kV, x = 0.15 pu 80 MVA, 13.2 A/165 Y kV, X = 0.1 pu 40 MVA, 165 Y/13.8 A kV, X = 0.1 pu 40 MVA, 0.8 PF lagging, operating at 150 kV Figure 2: Equipment ratings for Problem 3.49. Part 1 Task: As requested by problem 3.49, provide a sketch of the per-unit equivalent circuit on the system base; show work for any per-unit conversions performed. The sketch should have the per-unit reactance of each system component; do not sum up any reactances that are in series. Model the load as a parallel combination of resistance and inductance. By selecting a common base of 100 MVA (PowerWorld's default) and 132 kV at the transmission line loop, draw an impedance diagram showing all impedances in per-unit. Figure 2 contains all necessary data. Generator G₁: Generator G₂: three-phase A-Y transformer T₁: three-phase Y-A transformer T₂: Load: 50 MVA, 13.2 kV, x = 0.15 pu 20 MVA, 13.8 kV, x = 0.15 pu 80 MVA, 13.2 A/165 Y kV, X = 0.1 pu 40 MVA, 165 Y/13.8 A kV, X = 0.1 pu 40 MVA, 0.8 PF lagging, operating at 150 kV Figure 2: Equipment ratings for Problem 3.49. Part 1 Task: As requested by problem 3.49, provide a sketch of the per-unit equivalent circuit on the system base; show work for any per-unit conversions performed. The sketch should have the per-unit reactance of each system component; do not sum up any reactances that are in series. Model the load as a parallel combination of resistance and inductance.

Answer rating: 100% (QA)

Step 11 Base MVAb new 100 MVA Base KVb new 220 ... View the full answer