import java.util.Scanner;

// Calculates the sum of odd digits of the input integer number
// Example: number = 12345   Sum = 9 (1+3+5)
//          number = 248     Sum = 0
//          number = 65732098 Sum = 24 (5+7+3+9)


public class SumOfOddDigits
{
public static void main(String[] args)
{
String digits = "48596732 273457 13579 24680 3";    
 Scanner in = new Scanner(digits);

while (in.hasNextInt())
{
int num;
num = in.nextInt();

int sum = 0;
int digit;

//-----------Start below here. To do: approximate lines of code = 5
// Use a while loop. While num is greater than 0, use the modulus operator to strip off the next digit.
// Check if this digit is odd, if so add it to sum variable
// Finally, divide the num by 10 to throw away the current digit



// Only add digit if it is odd






//-----------------End here. Please do not remove this comment. Reminder: no changes outside the todo regions.
System.out.println("The sum is " + sum);
}
System.out.println("Expected:");
System.out.println("The sum is 24");
System.out.println("The sum is 22");
System.out.println("The sum is 25");
System.out.println("The sum is 0");
System.out.println("The sum is 3");
}
}

Answer rating: 100% (QA)

import javautilScanner public class SumOfOddDigits public static void mainString args String ... View the full answer