In a game two dice are thrown. Let one die be "weighted" so that a 2 shows up with probability 3/10, and 3, shows up with probability 3/10 while its other numbers all have equal probabilities. The same probabilities apply to the other die except the number 1 and number 6 are "weighted." 

Determine the probability the shooter will win outright by having the sum of the numbers showing up be 9?

اخترأحد الخيارات

a. 0.1563

b. 0.1389

c. 0.1200

d. 0.1500

Answer rating: 100% (QA)

for the dice first say D1 Probability of 2 P2 310 probabilit... View the full answer