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# n rope is fixed to a wall and attached to the block such that the rope is parallel to the surface of the wedge. The

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## rope is fixed to a wall and attached to the block such that the rope is parallel to the surface of the wedge. The 12 points) Consider the situation in the figure where a square block (mi) sits stop, a triangular wedge (m2). A tion with the same static coefficient us. The system is in equilibrium but if the coefficient of friction between wedge's top surface makes an angle of theta with respect to the horizontal. Assume that all surfaces have fric- the block and wedge was any smaller, they would slide relative to each other. The block (m = m) has a mass half as large as the wedge. (a) Draw a free body diagram for m. FBD (M.) Mi M Ymg Use a coordinate system with positive x up the incline and positive y perpendicular to the wedge's incline. Write out Newton's 2nd law in both the x and y directions for box m. Your answer should be in terms of m, 0, FT, s, FN (21), and g. Identify any quantities that are zero. There is no need to solve for anything (i.e. don't solve for a variable in one direction and plug it into the other direction). My {Fx =max FT + M FN - Mg sind = max o Fy = May FN - mg cose = may Rubric ~~ Part (a) -2 points 0.5 pts each correct force Part (b)-3 points 1.5 pts Fnet in the x-direction 1.5 pts Fnet in the y-direction Part (c)-1 point 0.5 pts each 3rd law force pair Part (d)-2.5 points 0.5 pts each correct force Part (e) 3.5 points 2 pts - correct 2nd law consistent w/ FBD

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Lets tackle the problem stepbystep Part a Drawing the Free Body Diagram FBD We need to draw the forces acting on the block m1 denoted as m in the diag...### Get Instant Access to Expert-Tailored Solutions

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