QUESTION 4 c) A parachutist bails out of an aeroplane and is in free fall for...
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QUESTION 4 c) A parachutist bails out of an aeroplane and is in free fall for a time of 4 seconds as shown in the diagram below. At a point, the parachute opens and thereafter, the parachutist reaches the ground with a speed of 3 m s. If the total distance of the fall is 950m. What is the deceleration rate after open the parachute (acceleration is constant after open the parachute) ? Note: acceleration due to gravity, g = 9.8 m s-2 v=v₁ + at v² = v + 2a (x-xo) 1 = at² + vot + xo x = Vo=0 m s¹_ Free Fall t=4s (a) (b) QUESTION 4 c) A parachutist bails out of an aeroplane and is in free fall for a time of 4 seconds as shown in the diagram below. At a point, the parachute opens and thereafter, the parachutist reaches the ground with a speed of 3 m s. If the total distance of the fall is 950m. What is the deceleration rate after open the parachute (acceleration is constant after open the parachute) ? Note: acceleration due to gravity, g = 9.8 m s-2 v=v₁ + at v² = v + 2a (x-xo) 1 = at² + vot + xo x = Vo=0 m s¹_ Free Fall t=4s (a) (b)
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Answer rating: 100% (QA)
Answer Velocity after 4 seconds is vv gt 0980 ms 40 s 392 ms ... View the full answer
Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
Posted Date:
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