The IP address is 192.169.0.144

8 subnets need to be created

is the solution below correct or not if not why please explain.

 

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IP Address: 192.169.0. 144, Class C: 192-223, Default subnet mask = 255-55.255.0 111111111111111111111111.00000000 192.169.0.144/24 Subnet 8 4 16 32 64 128 256 12 2 1 84 256 128 64 32 16 Subnet Mask /24 /25/26/27/28/29/30/31/32 Host Network Subnet ID I Mosk Host ID Range 2-163.0.144 127 /24 /27 192.163 0.196 192.168.0.208 192.168.0.2.40 190.163.0.2.72 192.163.0-304 192.163.0.336 192.168.0.368 192.169.0.145 192.168.0.197 192.168.0.309 /27 132.168.0.244 /27 192-163-0.273 /27 192.169.0.305 /27 192.169-0.337 127 192.168.0.369 of Usable Host ID 30 30 30 30 30 30 Thus CIDR volue = /24 30 30 Broadcast ID 32 is the number of each network total id's Jast the host is reserved for the broadcast 11 and the for the network 110 P 192.169.0.175 192.169.0.203 192.169-0.239 192.168.0.271 192-169.0.303 192.168.0.335 192.169.0.367 192.169.0.399 first Thus # of Usoole Host 10 = 2 = 38-2 = 30 Hast Range - Any ID's between the Net. 110 Broadcast 10 Network ID-The first one is always the original one, the next ones are generated by adding the host number of 32 to each and every one. IP Address: 192.169.0. 144, Class C: 192-223, Default subnet mask = 255-55.255.0 111111111111111111111111.00000000 192.169.0.144/24 Subnet 8 4 16 32 64 128 256 12 2 1 84 256 128 64 32 16 Subnet Mask /24 /25/26/27/28/29/30/31/32 Host Network Subnet ID I Mosk Host ID Range 2-163.0.144 127 /24 /27 192.163 0.196 192.168.0.208 192.168.0.2.40 190.163.0.2.72 192.163.0-304 192.163.0.336 192.168.0.368 192.169.0.145 192.168.0.197 192.168.0.309 /27 132.168.0.244 /27 192-163-0.273 /27 192.169.0.305 /27 192.169-0.337 127 192.168.0.369 of Usable Host ID 30 30 30 30 30 30 Thus CIDR volue = /24 30 30 Broadcast ID 32 is the number of each network total id's Jast the host is reserved for the broadcast 11 and the for the network 110 P 192.169.0.175 192.169.0.203 192.169-0.239 192.168.0.271 192-169.0.303 192.168.0.335 192.169.0.367 192.169.0.399 first Thus # of Usoole Host 10 = 2 = 38-2 = 30 Hast Range - Any ID's between the Net. 110 Broadcast 10 Network ID-The first one is always the original one, the next ones are generated by adding the host number of 32 to each and every one.

Answer rating: 100% (QA)

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