In Exercise 3.52 on page 189, we discuss a Gallup poll stating that the proportion of American adults getting health insurance from an employer is estimated to be 0.45. We are also told that, with 95% confidence, €˜€˜the maximum margin of sampling error is±1 percentage point€ for this estimate. In fact, the Gallup organization rounded up the margin of error to the nearest whole number and the actual margin of error is quite a bit less. Figure B.10 shows a bootstrap distribution based on the sample results. Use the bootstrap distribution to estimate the standard error and find and interpret a 95% confidence interval. 

Figure B.10

Exercise 3.52 on page 189

A report from a Gallup poll in 2011 started by saying, €˜€˜Forty-five percent of American adults reported getting their health insurance from an employer...€ Later in the article we find information on the sampling method, €˜€˜a random sample of 147,291 adults, aged 18 and over, living in the US,€ and a sentence about the accuracy of the results, €˜€˜the maximum margin of sampling error is ±1 percentage point.€

Transcribed Image Text:

300 Two-Tail O Right Tail # samples - 10,000 Left Tail mean = 0.450 250 - st.dev. = 0.001 200- 150 100 50 0.446 0.447 0.448 0.449 0.451 0.452 0.453 0.454 0.455 0.450