Under the null hypothesis H₀: p₁= p₂of equal population proportions, the standard error for the difference in the two sample proportions mentioned on page 494 reduces to se₀= ˆš(b + c)/n², where b and c are the off-diagonal elements and n is the number of subjects.
a. Show that the null standard error se0 equals 0.010 for the contingency table in Table 10.18.
b. Compute the value of the test statistic

and verify that is b - c/ˆšb + c The P-value in the computer output of Table 10.19 refers to this test statistic.

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(P1 – P2) – 0 estimate – null value estimate seo seo