The velocity of a 3.00 kg particle is given by v = (8.00ti + 3.00t2j) m/s, with
Question:
The velocity of a 3.00 kg particle is given by v = (8.00ti + 3.00t2j) m/s, with time t in seconds. At the instant the net force on the particle has a magnitude of 35.0 N, what is the direction (relative to the positive direction of the x axis) of
(a) The net force and
(b) The particle's direction of travel?
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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