A metal, M, was converted to the sulfate,M2(SO4)3. Then a solution of the sulfate was treated with
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M2(SO4)3(aq) + 3BaCl2(aq) → 2MCl3(aq) + 3BaSO4(s)
If 1.200 g of the metal gave 6.026 g of barium sulfate, what is the atomic weight of the metal? What is the metal?
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Convert the 6026 g of BaSO 4 to moles of BaSO 4 then from the equation deduce ...View the full answer
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