(a) One way of defining sec-1 x is to say that y = sec-1x sec y =...
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(b) Another way of defining sec-1 that is sometimes used is to say that y = sec-1x ↔ sec y = x and 0 < y < π y ≠ 0. Show that, with this definition, d/dx (sec-1 x) = 1 / x√x2 – 1
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