A small bar magnet of mass 0.1 kg, length 1 cm, and magnetic moment = 0.04
Question:
A small bar magnet of mass 0.1 kg, length 1 cm, and magnetic moment μ = 0.04 A · m2 is located at the center of a 100-turn loop of 0.2 m diameter. The loop carries a current of 5.0 A. At equilibrium, the bar magnet is aligned with the field due to the current loop. The bar magnet is given a displacement along the axis of the loop and released. Show that if the displacement is small, the bar magnet executes simple harmonic motion, and find the period of this motion.
Step by Step Answer:
We shall do this problem for the general case of a magnetic moment in a coil of N turns T...View the full answer
Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry
Related Video
simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side. The time interval of each complete vibration is the same
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