An object thrown the edge of a 42-foot cliff follows the path given by y = 2x2
Question:
a. Find the position of the object when it is closest to the observer.
b. Find the position of the object when it is farthest from the observer.
Transcribed Image Text:
42 ft
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a We can solve the equation 2x 2 25 x 42 0 to find the value for x when the object hits the ground W...View the full answer
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