As part of a project to develop better lawn fertilizers, a research chemist wanted to determine the mean weekly growth rate of Kentucky bluegrass, a common type of grass. A sample of 250 blades of grass was measured, and the amount of growth in 1 week was recorded. Assuming that weekly growth is normally distributed with a standard deviation of .10 inch, estimate with 99% confidence the mean weekly growth of Kentucky bluegrass. Briefly describe what the interval estimate tells you about the growth of Kentucky bluegrass.
Answer to relevant QuestionsA time study of a large production facility was undertaken to determine the mean time required to assemble a cell phone. A random sample of the times to assemble 50 cell phones was recorded. An analysis of the assembly times ...The sponsors of television shows targeted at the children’s market wanted to know the amount of time children spend watching television because the types and number of programs and commercials are greatly influenced by ...a. Repeat part (b) of Exercise 10.48 after discovering that the population standard deviation is actually 100.b. Repeat part (b) of Exercise 10.48 after discovering that the population standard deviation is actually 400.a. From the information given here determine the 95% confidence interval estimate of the population mean.x̄ = 100 σ = 20 n = 25b. Repeat part (a) with x = 200.c. Repeat part (a) with x = 500.d. Describe what happens to the ...H0: µ = 100H1: µ ≠ 100σ = 10, n = 100, x̄ = 100, α = .05Calculate the value of the test statistic, set up the rejection region, determine the p-value, interpret the result, and draw the sampling distribution.
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