Consider the data from Exercise 11.S.5. For these data, SS(ozone) = 0.696, SS(sulfur) = 0.492, SS(interaction) =

Question:

Consider the data from Exercise 11.S.5. For these data, SS(ozone) = 0.696, SS(sulfur) = 0.492, SS(interaction) = 0.166, and SS(within) = 0.275.
(a) Prepare an interaction graph (like Figure 11.7.3).
(b) Construct the ANOVA table.
(c) What is the value of the F test statistic for interactions?
(d) The P-value for the interactions F test is 0.058. If α = 0.05, what is your conclusion regarding the null hypothesis?
(e) The P-value for testing that ozone has no effect is 0.0019. If α = 0.05, what is your conclusion regarding the null hypothesis?