# Question

Differentiating with respect to θ the expressions on both sides of the equation

Show that the mean of the geometric distribution is given by µ = 1/θ. Then, differentiating again with respect to θ, show that µ'2 = 2 – θ / θ2 and hence that σ2 = 1 – θ / θ2.

Show that the mean of the geometric distribution is given by µ = 1/θ. Then, differentiating again with respect to θ, show that µ'2 = 2 – θ / θ2 and hence that σ2 = 1 – θ / θ2.

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