# Question: Explain whether each of the following is possible a A relationship

Explain whether each of the following is possible.

a. A relationship exists in the observed sample but not in the population from which the sample was drawn.

b. A relationship does not exist in the observed sample but does exist in the population from which the sample was drawn.

c. A relationship does not exist in the observed sample, but an analysis of the sample shows that there is a statistically significant relationship, so it is inferred that there is a relationship in the population. Exercises 28 to 33 are based on News Story 2, “Research shows women harder hit by hangovers” and the accompanying Original Source 2. In the study, 472 men and 758 women, all of whom were college students and alcohol drinkers, were asked about whether they had experienced each of 13 hangover symptoms in the previous year.

a. A relationship exists in the observed sample but not in the population from which the sample was drawn.

b. A relationship does not exist in the observed sample but does exist in the population from which the sample was drawn.

c. A relationship does not exist in the observed sample, but an analysis of the sample shows that there is a statistically significant relationship, so it is inferred that there is a relationship in the population. Exercises 28 to 33 are based on News Story 2, “Research shows women harder hit by hangovers” and the accompanying Original Source 2. In the study, 472 men and 758 women, all of whom were college students and alcohol drinkers, were asked about whether they had experienced each of 13 hangover symptoms in the previous year.

**View Solution:**## Answer to relevant Questions

What population do you think is represented by the sample for this study? Explain. Refer to the previous exercise about hangover symptoms. Use the Minitab output at the top of the page for this exercise. a. Show how the expected count of 343.27 for the “Male, # 11” category was computed. b. Give the ...For each of the following situations, would a chi-square test based on a 232 table using a level of 0.05 be statistically significant? Justify your answer. a. chi-square statistic = 1.42 b. chi-square statistic = 14.2 c. ...According to Krantz (1992, p. 111), the probability of being born on a Friday the 13th is about 1/214. a. What is the probability of not being born on a Friday the 13th? b. In any particular year, Friday the 13th can occur ...Suppose you play a carnival game that requires you to toss a ball to hit a target. The probability that you will hit the target on each play is .2 and is independent from one try to the next. You win a prize if you hit the ...Post your question