Find all complex numbers z such that: (a) z4 = 2/(3i - 1) (b) z6 = -
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(a) z4 = 2/(√3i - 1)
(b) z6 = - 64
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a Write z re i Then z 4 23i 1 becomes r 4 e 4i 4e 2i3 Hence r 4 4 so r 2 and 4 23 2k th...View the full answer
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