Find the critical points and the extreme values on [0, 4]. 53. y = |x 2| 55.
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53. y = |x 2|
55. y = |x2 + 4x 12|
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30 20 -6 y-2 12 ycos x FIGURE 18
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53 Let f x x 2 For x 2 we have fx 1 For x 2 we have fx 1 Now as x 2 we have wher...View the full answer
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