Identify the C6H14 isomers on the basis of their 13C NMR spectra: (a) 19.1 ppm (CH3)
Question:
(a) δ 19.1 ppm (CH3)
δ 33.9 ppm (CH)
(b) δ 13.7 ppm (CH3)
δ 22.8 ppm (CH2)
δ 31.9 ppm (CH2)
(c) δ 11.1 ppm (CH3)
δ 18.4 ppm (CH3)
δ 29.1 ppm (CH2)
δ 36.4 ppm (CH)
(d) δ 8.5 ppm (CH3)
δ 28.7 ppm (CH3)
δ 30.2 ppm (C)
δ 36.5 ppm (CH2)
(e) 14.0 ppm (CH3)
δ 20.5 ppm (CH2)
δ 22.4 ppm (CH3)
δ 27.6 ppm (CH)
δ 41.6 ppm (CH2)
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The molecular formula of C 6 H 14 for each of these isomers ...View the full answer
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