In a meeting of mimes, mime 1 goes through a displacement d1 = (4.0 m)i + (5.0
Question:
In a meeting of mimes, mime 1 goes through a displacement d1 = (4.0 m)i + (5.0 m)j and mime 2 goes through a displacement d2 = (– 3.0 m)i + (4.0 m)i. What are?
(a) d1 x d2
(b) d1 ∙ d2
(c) (d1 + d2) and
(d) The component of d1 along the direction of d2?
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The two vectors are written as in unit of meters d 4050 dd d3040dd a The vector cross prod...View the full answer
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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