Locate the center of gravity xc of the homogeneous rod bent in the form of a semicircular
Question:
Locate the center of gravity xc of the homogeneous rod bent in the form of a semicircular arc. The rod has a weight per unit length γ. Also, determine the horizontal reaction at the smooth support B and the x and y components of reaction at the pin A.
Given:
γ = 0.5lb/ft
r = 2 ft
rde B,
Step by Step Answer:
Xc Eld 2 2 rcoser de ELN 5 2 ...View the full answer
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