A proton, a deuteron (q = +e, m = 2.0 u), and an alpha particle (q =
Question:
A proton, a deuteron (q = +e, m = 2.0 u), and an alpha particle (q = +2e, m = 4.0 u) are accelerated through the same potential difference and then enter the same region of uniform magnetic field B, moving perpendicular to B. What is the ratio of?
(a) The proton's kinetic energy K p to the alpha particle's kinetic energy K α and
(b) The deuteron's kinetic energy K d to K α? If the radius of the proton's circular path is 10 cm, what is the radius of?
(c) The deuteron's path and
(d) The alpha particle's path?
Step by Step Answer:
a Since K qV we have K K as q 2K or KK 050 b Simil...View the full answer
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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