Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on
Question:
Show that the sum N1 + N2 + N3 + N4 is equal to 1 anywhere on a rectangular element, where N1 through N4 are defined by Eqs. (6.6.5).
In Eqs (6.6.5)
Transcribed Image Text:
(b — х)(h — у) N2 4bh (b + x)(h – y) 4bh N1 (b + x)(h + y) 4bh (b – x)(h + y) N3 = N4 4bh ||
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at center x 0 y 0 N 1 N 2 N 3 N 4 1 At point x ...View the full answer
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Related Book For
A First Course in the Finite Element Method
ISBN: 978-1305635111
6th edition
Authors: Daryl L. Logan
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