Find the surface area of the part of the cone (x^{2}+y^{2}=z^{2}) between the planes (z=2) and (z=5).

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Find the surface area of the part of the cone $x^{2}+y^{2}=z^{2}$ between the planes $z=2$ and $z=5$.

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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Question Posted: Jan 24, 2024 08:02 AM

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Find the surface area of the part of the cone (x^{2}+y^{2}=z^{2}) between the planes (z=2) and (z=5).

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We use the following parametrization of the surface S beginaligned Phiu vu cos v u sin v u mathcalD ...View the full answer

Calculus

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