Let (x) = x 5 + x 2 . The secant line between (0, 0) and (1,
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Let ƒ(x) = x5 + x2. The secant line between (0, 0) and (1, 2) has slope 2 (check this), so by the MVT, ƒ'(c) = 2 for some c ∈ (0, 1). Plot f and the secant line on the same axes. Then plot y = 2x + b for different values of b until the line becomes tangent to the graph of ƒ. Zoom in on the point of tangency to estimate the x-coordinate c of the point of tangency.
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Let fx x x The slope of the secant line between x 0 and x 1 is 20 1 0 10 1 2 A plot of ...View the full answer
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