The area function F(x) x 0 1 t 2 dt is an antiderivative of (x) 1 x 2 Prove the formula using geometry by interpreting the integral as the area of part of the unit circle 1 1 VI Pdt sin x x V Vi 2 S 0...

The integral So 1 1 dt is the area bounded by the unit circle the ...

The area function F(x) = x 0 1 t 2 dt is an antiderivative of

Question:

The area function F(x) = ∫^x₀√1 − t²dt is an antiderivative of ƒ(x) = √1 − x². Prove the formula

1 1 *VI-Pdt = sin x + x V - Vi 2 S 0

using geometry by interpreting the integral as the area of part of the unit circle.

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Calculus

ISBN: 9781319055844

4th Edition

Authors: Jon Rogawski, Colin Adams, Robert Franzosa

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Question Posted: Dec 01, 2023 08:03 AM

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The area function F(x) = x 0 1 t 2 dt is an antiderivative of

Question:

1 1 *VI-Pdt = sin ¹² x + x V₁ -² √ Vi 2 S 0

Step by Step Answer:

The integral So 1 1 dt is the area bounded by the unit circle the ...View the full answer

Calculus

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