Prove that (log b c) (log c b) = 1, for b > 0, c > 0,
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Prove that (logb c) (logc b) = 1, for b > 0, c > 0, b ≠ 1, and c ≠ 1.
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Related Book For
Calculus Early Transcendentals
ISBN: 978-0321947345
2nd edition
Authors: William L. Briggs, Lyle Cochran, Bernard Gillett
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