The velocity of a skydiver (in m/s) t seconds after jumping from a plane is v(t) =
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The velocity of a skydiver (in m/s) t seconds after jumping from a plane is v(t) = 600(1 - e-kt/60)/k, where k > 0 is a constant. The terminal velocity of the skydiver is the value that v(t) approaches as t becomes large. Graph v with k = 11 and estimate the terminal velocity.
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Related Book For
Calculus Early Transcendentals
ISBN: 978-0321947345
2nd edition
Authors: William L. Briggs, Lyle Cochran, Bernard Gillett
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