The equilibrium constant for the following reaction is (1.0 times 10^{23}) : EDTA is used as a

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The equilibrium constant for the following reaction is \(1.0 \times 10^{23}\) :

Cr+ (aq) + HEDTA (aq) CrEDTA-(aq) + 2H+ (aq) -0C-CH CH,CO, CH,CO, EDTA- = -0C-CH N-CH-CH-N

EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt \(\mathrm{Na}_{2} \mathrm{H}_{2}\) EDTA, are used to treat heavy metal poisoning. Calculate \(\left[\mathrm{Cr}^{3+}ight]\) at equilibrium in a solution originally \(0.0010 \mathrm{Min}^{3+}\) and \(0.050 \mathrm{M}\) in \(\mathrm{H}_{2}\) EDTA \(^{2-}\) and buffered at \(\mathrm{pH}=6.00\).

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Chemical Principles

ISBN: 9780618946907

6th Edition

Authors: Steven S Zumdahl

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