Lead ions can be precipitated from solution with KCl according to the reaction:

When 28.5 g KCl is added to a solution containing 25.7 g Pb^2 + , a PbCl₂ precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.4 g. Determine the limiting reactant, theoretical yield of PbCl2, and percent yield for the reaction.

Transcribed Image Text:

Pb²+ (aq) + 2 KCl(aq) PbCl₂(s) + 2 K+ (aq)