You mix 25.0 mL of 0.234 M FeCl 3 with 42.5 mL of 0.453 M NaOH. (a)
Question:
You mix 25.0 mL of 0.234 M FeCl3 with 42.5 mL of 0.453 M NaOH.
(a) What mass of Fe(OH)3 (in grams) will precipitate from this reaction mixture?
(b) One of the reactants (FeCl3 or NaOH) is present in a stoichiometric excess. What is the molar concentration of the excess reactant remaining in solution after Fe(OH)3 has been precipitated?
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a To calculate the mass of FeOH3 that will precipitate from the reaction mixture we first need to determine the limiting reactant FeCl3aq 3NaOHaq FeOH...View the full answer
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Related Book For
Chemistry And Chemical Reactivity
ISBN: 9780357001172
10th Edition
Authors: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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