If air resistance is ignored, the height h of a projectile above the ground after x seconds

Question:

If air resistance is ignored, the height h of a projectile above the ground after x seconds is given by h(x) = -1/2gx + v0x + h0 where g is the acceleration due to gravity. This formula is also valid for other celestial bodies. Suppose a ball is thrown straight up at v0= 88 feet per second from a height of h0= 25 feet. 

(a) For the given g, graphically estimate both the maximum height and the time when it occurs. 

(b) Solve part (a) symbolically.

g = 88 (Jupiter)

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question
Question Posted: