If air resistance is ignored, the height h of a projectile above the ground after x seconds is given by h(x) = -1/2gx + v₀x + h₀ where g is the acceleration due to gravity. This formula is also valid for other celestial bodies. Suppose a ball is thrown straight up at v₀= 88 feet per second from a height of h₀= 25 feet. 

(a) For the given g, graphically estimate both the maximum height and the time when it occurs. 

(b) Solve part (a) symbolically.

g = 32 (Earth)