A proton moves at 7.50 x 10 7 m/s perpendicular to a magnetic field. The field causes
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A proton moves at 7.50 x 107 m/s perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius 0.800 m. What is the field strength?
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Given Proton velocity v 750 x 107 ms Protons radius r 0800 m For...View the full answer
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