A phase lead compensator has the transfer function [ mathrm{G}_{c}(s)=frac{10(1+0.04 s)}{(1+0.01 s)} ] The maximum phase angle

Question:

A phase lead compensator has the transfer function

\[
\mathrm{G}_{c}(s)=\frac{10(1+0.04 s)}{(1+0.01 s)}
\]

The maximum phase angle lead provided by this compensator will occur at a frequency $\omega_{m}$ equal to
(a) $50 \mathrm{rad} / \mathrm{sec}$
(b) $25 \mathrm{rad} / \mathrm{sec}$
(c) $10 \mathrm{rad} / \mathrm{sec}$
(d) $4 \mathrm{rad} / \mathrm{sec}$

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