The elevator starts from rest at the first floor of the building. It can accelerate at rate
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The elevator starts from rest at the first floor of the building. It can accelerate at rate a1 and then decelerate at rate a2. Determine the shortest time it takes to reach a floor a distance d above the ground. The elevator starts from rest and then stops. Draw the a-t, v-t, and s-t graphs for the motion. Given:
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Guesses tj 1s t 2 s dj 20 ft Vmax 1 S Given 2201112 d ...View the full answer
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Balvinder Singh
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