Liquid water enters a steady state heat exchanger at P =10 bar and T = 80C, and

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Liquid water enters a steady state heat exchanger at P =10 bar and T = 80°C, and exits as saturated water vapor at P = 10 bar.

A. Using the steam tables, find the change in specific enthalpy for this process.

B. Using the approximation that C_p = 4.19 J/g · K for liquid water, find the change in enthalpy when liquid water is heated from 80°C to its boiling point at P = 10 bar.

C. How do the answers to parts A and B compare to each other? What is the reason for the difference between them?

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Fundamentals Of Chemical Engineering Thermodynamics

ISBN: 9781111580704

1st Edition

Authors: Kevin D. Dahm, Donald P. Visco

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Question Posted: Nov 06, 2023 10:18 AM

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Liquid water enters a steady state heat exchanger at P =10 bar and T = 80C, and

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A At P 10 bar and T 80C the specific enthalpy of liquid water is h 33695 kJkg At P 10 bar the specif...View the full answer

Fundamentals Of Chemical Engineering Thermodynamics

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