SEGMENTATION: The size of the physical memory is 4500 K with the starting address 1. The...

 

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SEGMENTATION: The size of the physical memory is 4500 K with the starting address 1. The first 500k is allocated for the resident OS. Process 1 is to be loaded into the memory with the following segment table of process 1. Note: Segment 0 (SO) and segment 1 (S1) of Process 1 are shown in the diagram to give examples. Continue loading the process 1 with S2 and S3 into the memory Contents of Memory: P1 Process 1 Segment table 1 Segment # Limit(k) Base(k) OS 0 150 3400 500k 1 350 4150 2 500 2100 3 1000 900 3400k SO 3550k 4150k S1 4500k Questions: A: What are the physical addresses or the following logical addresses of P1? If the address generates a segment fault, indicate so. 1.) 0,100 = 2.) 1, 4150 = 3.) 2,400 = 4.) 3,900 = SEGMENTATION: The size of the physical memory is 4500 K with the starting address 1. The first 500k is allocated for the resident OS. Process 1 is to be loaded into the memory with the following segment table of process 1. Note: Segment 0 (SO) and segment 1 (S1) of Process 1 are shown in the diagram to give examples. Continue loading the process 1 with S2 and S3 into the memory Contents of Memory: P1 Process 1 Segment table 1 Segment # Limit(k) Base(k) OS 0 150 3400 500k 1 350 4150 2 500 2100 3 1000 900 3400k SO 3550k 4150k S1 4500k Questions: A: What are the physical addresses or the following logical addresses of P1? If the address generates a segment fault, indicate so. 1.) 0,100 = 2.) 1, 4150 = 3.) 2,400 = 4.) 3,900 =

Answer rating: 100% (QA)

A 1 Logical address 0 maps to physical address 3400 2 Lo... View the full answer