The metabolism of glucose, C 6 H 12 O 6 , yields CO 2 (g) and H
Question:
The metabolism of glucose, C6H12O6, yields CO2(g) and H2O(l) as products. Heat released in the process is converted to useful work with about 70% efficiency. Calculate the mass of glucose metabolized by a 58.0 kg person in climbing a mountain with an elevation gain of 1450 m. Assume that the work performed in the climb is about four times that required to simply lift 58.0 kg by 1450 m. (¢fH° C6H12O61s2 is -1273.3 kJ>mol.2
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Given data Mass of the person 580 kg Elevation gain 1450 m Work efficiency 70 Standard molar enthalp...View the full answer
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Related Book For 
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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