What is G at 25C for the reaction Sn 2+ (aq) + 2Hg 2+ (aq) Sn
Question:
What is ∆G° at 25°C for the reaction
Sn2+(aq) + 2Hg2+(aq) → Sn4+(aq) + Hg22+(aq)
For data, see Table 19.1.
Transcribed Image Text:
Table 19.1 Standard Electrode (Reduction) Potentials in Aqueous Solution at 25°C Standard Cathode (Reduction) Half-Reaction Potential, E(V) Li*(ag) + e"= Li(s) - 3.04 Na"(aq) + e"= Na(s) -2.71 Mg"(ag) + 2e" = Mg(s) -2.38 AP* (ag) + 3e" = Al(s) -1.66 2H,O(1) + 2e"= Hlg) + 20H"(ag) -0.83 Zn"(ag) + 2e = Zn(s) -0.76 Cr*(aq) + 3e" Cris) -0.74 Fe" (ag) + 2e" Fe(s) -0.41 Cd*(ag) + 2e" = Cd(s) -0.40 Ni*(aq) + 2e" = Ni(s) -0.23 Sn"(ag) + 2e Sn(s) -0.14 Pb*(ag) + 2e" = Pb(s) -0.13 Fe" (ag) + 3e" = Fe(s) -0.04 2H (ag) + 2e H,(g) 0.00 Sn" (ag) + 2e"= Sn" (ag) 0.15 Cu**(aq) + e"= Cu*(ag) Cu**(ag) + 2e"= Cu(s) 10"(ag) + H,O) + 20"=1"(ag) + 20H" (ag) 0.16 0.34 0.49 Cu'(ag) + e= Cu(s) 0.52 0.54 L(s) + 2e"= 21"(ag) Fe"(ag) + e= Fe*(ag) 0.77 Hg;" (ag) + 2e =2Hg(/) 0.80 Ag'(ag) + e" Ag(s) 0.80 Hg"(ag) + 2e" = Hg(/) 0.85 CIO"(ag) + H,O() + 2e"= CI"(aq) + 20H"(ag) 2Hg" (aq) + 2e" = Hg," (ag) NO," (ag) + 4H (ag) + 3e"= NO(g) + 2H,01) 0.90 0.90 0.96 Brl) + 2e" 2Br"(ag) 1.07 Odg) + 4H"(ag) + 4e"= 2H,0(7) 1.23 Cr,O,- (ag) + 14H (ag) + 6e"= 2C"(ag) + 7H,0(1) 1.33 Cl,g) + 2e"= 2C"(ag) 1.36 Mno,"(aq) + SH (aq) + Se" Mn** (ag) + 4H,0(1) 1.49 H,O(ag) + 2H"(aq) + 2e"= 2H,0(1) 1.78 S,0,- (ag) + 2e-=280,"(ag) 2.01 FAg) + 2e" 2F"(ag) 287
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