If the adsorption process described in Problem 3.17 took place cocurrently, calculate the minimum flow rate of activated carbon required.

Data From Problem 3.17:-

Activated carbon is used to recover benzene from a nitrogen-benzene vapor mixture. The mixture, at $306 \mathrm{~K}$ and $1 \mathrm{~atm}$ containing $1.0 \%$ benzene by volume, is to be passed countercurrently at the rate of $1.0 \mathrm{~m}^{3} / \mathrm{s}$ to a moving stream of activated carbon so as to remove $85 \%$ of the benzene from the gas in a continuous process. The entering activated carbon contains $15 \mathrm{~cm}^{3}$ of benzene vapor (at STP) adsorbed per gram of the carbon. The temperature and total pressure are maintained at $306 \mathrm{~K}$ and $1 \mathrm{~atm}$. Nitrogen is not adsorbed.

(a) Plot the equilibrium data given in the table below as $X^{\prime}=\mathrm{kg}$ benzene/kg dry carbon, $Y^{\prime}=\mathrm{kg}$ benzene/kg nitrogen for a total pressure of $1 \mathrm{~atm}$.

(b) Calculate the minimum flow rate required of the entering carbon (remember that the entering carbon contains some adsorbed benzene).

(c) If the carbon flow is $20 \%$ above the minimum, what will be the concentration of benzene adsorbed on the carbon leaving the process?

(d) For the conditions of part (c), calculate the number of ideal stages required.

The equilibrium adsorption of benzene on this activated carbon at the temperature of $306 \mathrm{~K}$ is reported as follows:

Transcribed Image Text:

Benzene vapor adsorbed, cm (STP)/g of carbon 15 Partial pressure of benzene, mm Hg 0.55 25 0.95 40 1.63 50 2.18 65 3.26 80 4.88 90 6.22 100 7.83