In a flat belt drive prove that (frac{T_{1}}{T_{2}}=e^{mu theta}); where (T_{1}) is tension in tight side, (T_{2})
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In a flat belt drive prove that \(\frac{T_{1}}{T_{2}}=e^{\mu \theta}\); where \(T_{1}\) is tension in tight side, \(T_{2}\) is tension in slack side, \(\mu\) is coefficient of friction, \(\theta\) is angle of lapin radian.
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