One suggestion for a simple pair potential is the triangular potential Derive the second virial coefficient and

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One suggestion for a simple pair potential is the triangular potentialu(r) =  for r < 0 and u(r) = 0 for r > Ro [(r/o) -R] 1-R u(r) = - -8 for o

Derive the second virial coefficient and fit the parameters σ, ε, and R to the virial coefficient data for argon tabulated in problem 7.30.


Data from Problem 7.30

The virial coefficient can be related to the pair potential by Eqn. 7.59.

(a) Derive the integrated expression for the second virial coefficient in terms of the squarewell potential parameters ε/k, σ, and R.

(b) Fit the parameters to the experimental data for argonT(K) 85 100 150 200 250 300 B (cm/mole) -251 -183.5 -86.2 -47.4 -27.9 -15.5 T(K) 400 500 600 700 800 900 B

(c) Fit the parameters to the experimental data for propane.T(K) 250 260 270 285 300 315 330 B (cm/mole) -584 -526 -478 -424 -382 -344 -313 T(K) 350 375 400 430 470 500

B = 00 2 N  (1 0 - exp(-#7)  dr kT 1- 7.59

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