Every countable set is a (lambda^{1})-null set. Use the Cantor ternary set (C) (see Problem 7.12) to
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Every countable set is a \(\lambda^{1}\)-null set. Use the Cantor ternary set \(C\) (see Problem 7.12) to illustrate that the converse is not true. What happens if we change \(\lambda^{1}\) to \(\lambda^{2}\) ?
Data from problem 7.12
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