The voltage across a capacitor is (V_{C}=q / C), where (C) is the capacitance and (q) is
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The voltage across a capacitor is \(V_{C}=q / C\), where \(C\) is the capacitance and \(q\) is the charge on the capacitor. The voltage across an inductor is \(V_{L}=L d I / d t\), where \(L\) is the inductance and \(I\) is the current through the inductor. A wire attached to a capacitor whose charge is changing carries a current \(I=d q / d t\). The net voltage drop around any closed circuit is zero, so a simple electrical \(L, C\) circuit obeys \(L \ddot{q}+q / C=0\), and so oscillates with frequency \(\omega=1 / \sqrt{L C}\). Find the normal mode oscillation frequencies of the three-loop circuit shown, for the case \(C_{1}=C_{2}=C_{3}=C\) and \(L_{1}=L_{2}=L_{12}=L_{23}=L\).
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